6x^2+110x-2000=0

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Solution for 6x^2+110x-2000=0 equation:



6x^2+110x-2000=0
a = 6; b = 110; c = -2000;
Δ = b2-4ac
Δ = 1102-4·6·(-2000)
Δ = 60100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{60100}=\sqrt{100*601}=\sqrt{100}*\sqrt{601}=10\sqrt{601}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(110)-10\sqrt{601}}{2*6}=\frac{-110-10\sqrt{601}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(110)+10\sqrt{601}}{2*6}=\frac{-110+10\sqrt{601}}{12} $

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